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Section8.2Focusing on normal subgroups

We first provide a theorem that will help us in identifying when a subgroup of a group is normal. First, we provide a definition.

Definition8.2.1

Let H be a subgroup of G and a,b in G\text{.} We define

\begin{equation*} aHb=\{ahb\,:h\in H\}. \end{equation*}
Proof

We now consider some examples and nonexamples of normal subgroups of groups.

Example8.2.3

  1. As previously mentioned, the trivial and improper subgroups of any group G are normal in G\text{.}

  2. As previously mentioned, if group G is abelian then each of its subgroups is normal in G\text{.}

  3. Suppose H\leq G has (G:H)=2\text{.} Then H \unlhd G\text{.} The proof of this is left as an exercise for the reader.

  4. Example 7.2.9 shows that subgroup H=\langle (12)\rangle isn't normal in S_3 (for example, (13)H\neq H(13)\text{.} But \langle (123)\rangle must be normal in S_3 since (S_3:\langle (123)\rangle )=6/3=2.

  5. \langle r\rangle is normal in D_n since (D_n:\langle r\rangle )=2\text{.}

  6. \langle f\rangle isn't normal in D_4\text{:} for instance,

    \begin{equation*} r\langle f\rangle r^{-1}=\{e,rfr^3\}=\{e, fr^3r^3\}=\{e,fr^2\}\not\subseteq \langle f\rangle . \end{equation*}

We consider two other very significant examples. First, we revisit the idea of the center of a group, first introduced in Example 2.8.9.

Definition8.2.4

Let G be a group. We let

\begin{equation*} Z(G)=\{z\in G\,:\, az=za \text{ for all } a\in G\}. \end{equation*}

Z(G) is called the center of G\text{.}

(The Z stands for “zentrum,” the German word for “center.”)

Proof
Proof

The next definition is profoundly important for us.

Definition8.2.7

Let G and G' be groups and let \phi a homomorphism from G to G'\text{.} Letting e' be the identity element of G'\text{,} we define the kernel of \phi, \Ker \phi\text{,} by

\begin{equation*} \Ker \phi = \{k\in G\,:\,\phi(k)=e'\}. \end{equation*}
Proof

One slick way, therefore, of showing that a particular set is a normal subgroup of a group G is by showing it's the kernel of a homomorphism from G to another group.

Example8.2.9

Let n\in \Z^+\text{.} Here is a rather elegant proof of the fact that SL(n,\R) is a normal subgroup of GL(n,\R)\text{:} Define \phi: GL(n,\R) \to \R^* by \phi(A)=\det A\text{.} Clearly, \phi is a homomorphism, and since the identity element of \R^* is 1,

\begin{equation*} \Ker \phi=\{A\in GL(n,\R)\,:\,\det A= 1\}=SL(n,\R). \end{equation*}

So SL(n,\R)\unlhd GL(n,\R)\text{.}